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【JAVA大數訓練】A + B Problem II
A + B Problem II
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 196702 Accepted Submission(s): 37626
Problem Description
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.
Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each
line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process
them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.
Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second
line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a
blank line between two test cases.
Sample Input
2
1 2
112233445566778899 998877665544332211
Sample Output
Case 1:
1 + 2 = 3
Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110
import java.math.BigInteger;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner input=new Scanner(System.in);
int n=input.nextInt();
int k=1;
while(n!=0)
{
BigInteger a=input.nextBigInteger();
BigInteger b=input.nextBigInteger();
BigInteger c=a.add(b);
n--;
if(k!=1)
System.out.println();//輸出換行
System.out.println("Case "+k+":");
k++;
System.out.println(a+" + "+b+" = "+c);
}
}
}
最後更新：2017-04-03 12:56:11