567
阿裏雲
技術社區[雲棲]
Android 通過網頁打開自己的APP(scheme)
Android 通過網頁打開自己的APP(scheme)
通過用手機的瀏覽器(內置,第三方都可)訪問一個網頁,實現點擊一個鏈接啟動自己的應用,並傳遞數據。
首先在Mainifest文件裏麵對要啟動的Activity添加一個過濾器。
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android:name = "com.example.helloworld.MainActivity"
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android:label = "@string/app_name" >
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< action android:name = "android.intent.action.MAIN" />
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< category android:name = "android.intent.category.LAUNCHER" />
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< action android:name = "android.intent.action.VIEW" />
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< category android:name = "android.intent.category.DEFAULT" />
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< category android:name = "android.intent.category.BROWSABLE" />
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< data android:scheme = "znn" />
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在MainActivity接收數據:
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public class MainActivity extends Activity implements View.OnClickListener{
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protected void onCreate(Bundle
savedInstanceState) {
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super .onCreate(savedInstanceState);
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setContentView(R.layout.activity_main);
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Intent
intent = getIntent();
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String
scheme = intent.getScheme();
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Uri
uri = intent.getData();
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System.out.println( "scheme:" +scheme);
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String
host = uri.getHost();
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String
dataString = intent.getDataString();
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String
id = uri.getQueryParameter( "id" );
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String
path = uri.getPath();
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String
path1 = uri.getEncodedPath();
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String
queryString = uri.getQuery();
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System.out.println( "host:" +host);
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System.out.println( "dataString:" +dataString);
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System.out.println( "id:" +id);
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System.out.println( "path:" +path);
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System.out.println( "path1:" +path1);
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System.out.println( "queryString:" +queryString);
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寫一個最簡單的網頁:
<a href=”znn://aa.bb:80/test?p=12&d=1″>test</a>
測試地址:www.erdian.net/m.html
測試結果:
scheme:znn
host:aa.bb
dataString:znn://aa.bb:80/test?p=12&id=1
id:1
path:/test
path1:/test
queryString:p=12&d=1
最後更新:2017-04-03 05:39:11