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uva 11210 - Chinese Mahjong 暴力回溯

   最近很頹廢,一直不想寫題,今天說寫題結果一直拖到現在才寫了一題……

   一個很簡單的模擬題,隻要會打麻將就會寫,注意牌不能超過4張的,編號的轉換有點累



/*
author:jxy
lang:C/C++
university:China,Xidian University
**If you need to reprint,please indicate the source**
*/
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <queue>
#define INF 1E9
using namespace std;
int num[40];
int s2i(char *s)
{
    switch(s[0])
    {
        case 'D':return 1;
        case 'N':return 2;
        case 'X':return 3;
        case 'B':if(s[1]=='E')return 4;
                 else return 7;
        case 'Z':return 5;
        case 'F':return 6;
        default:
        switch(s[1])
        {
            case 'T':return s[0]-'0'+10;
            case 'S':return s[0]-'0'+20;
            case 'W':return s[0]-'0'+30;
            default:return 0;
        }
    }
}
string ss[10]={"DONG","NAN","XI","BEI","ZHONG","FA","BAI"};
string oo[10]={"0","1","2","3","4","5","6","7","8","9"};
string i2s(int now)
{
    if(now<10)return ss[now-1];
    switch(now/10)
    {
        case 1:return oo[now%10]+"T";
        case 2:return oo[now%10]+"S";
        case 3:return oo[now%10]+"W";
        default:return "error";
    }
}
bool win(int two,int three,int i)
{
    if(i==40)return 0;
    if(num[i]==0)return win(two,three,i+1);
    if(two&&num[i]>=2)
    {
        if(!three)return 1;
        num[i]-=2;
        if(win(0,three,i)){num[i]+=2;return 1;}
        num[i]+=2;
    }
    if(three&&num[i]>=3)
    {
        if(three==1&&!two)return 1;
        num[i]-=3;
        if(win(two,three-1,i)){num[i]+=3;return 1;}
        num[i]+=3;
    }
    if(three&&num[i]&&i>10)
    {
        for(int t=-2;t<=0;t++)
        {
            if((i+t)/10!=(i+t+2)/10)continue;
            if(!num[i+t]||!num[i+t+1]||!num[i+t+2])continue;
            if(three==1&&!two)return 1;
            num[i+t]--;num[i+t+1]--;num[i+t+2]--;
            if(win(two,three-1,i)){num[i+t]++;num[i+t+1]++;num[i+t+2]++;return 1;}
            num[i+t]++;num[i+t+1]++;num[i+t+2]++;
        }
    }
    return 0;
}
void solve(int T)
{
    cout<<"Case "<<T<<":";
    bool flag=1;
    for(int i=11;i!=10;i++)//因為順序要求
    {
        if(!(i%10)||num[i]==4)continue;
        num[i]++;
        if(win(1,4,1)){cout<<" "<<i2s(i);flag=0;}
        num[i]--;
        if(i==39)i=0;
    }
    if(flag)cout<<" Not ready";
    cout<<endl;
}
bool input()
{
    char s[100];
    int i=0;
    memset(num,0,sizeof(num));
    do
    {
        i++;
        scanf("%s",s);
        if(s[0]=='0')return 0;
        num[s2i(s)]++;
    }while(i<13);
    return 1;
}
int main()
{
    int T=0;
    while(input())solve(++T);
}

/*
4T 5T 6T 6T 6T 6T 7T 8T 9T 9T 9T BAI BAI
4T 5T 6T 6T 6T 6T 7T 8T 9T 9T 9T 1W 1W
2T 3T 3T 3T 4T 4T 4T 5T 5T 6T 6T 7T 7T
1T 1T 2T 2T 2T 3T 3T 3T 4T 4T 5T 5T 5T
1T 1T 1T 2T 2T 3T 3T 3T 4T 4T 5T 5T 5T
1T 1T 1T 2T 2T 3T 3T 3T 4T 4T 5T 5T 6T
1T 1T 1T 2T 2T 3T 3T 3T 4T 4T 5T 6T 6T
1T 1T 1T 2T 2T 3T 3T 3T 4T 4T 6T 6T 6T
1T 1T 1T 2T 2T 3T 3T 3T 4T 5T 6T 6T 6T
1T 1T 1T 2T 2T 3T 3T 4T 4T 5T 6T 6T 6T
1T 1T 2T 2T 2T 3T 3T 4T 4T 5T 6T 6T 6T
1T 1T 2T 2T 3T 3T 3T 4T 4T 5T 6T 6T 6T
1T 1T 2T 2T 3T 3T 4T 4T 4T 5T 6T 6T 6T
1T 1T 2T 2T 3T 4T 4T 4T 4T 5T 6T 6T 6T
1T 2T 2T 2T 2T 3T 4T 4T 4T 5T 6T 6T 6T
2T 2T 2T 2T 3T 3T 4T 4T 4T 5T 6T 6T 6T
2T 2T 2T 2T 3T 3T 4T 4T 4T 5T 5T 6T 6T
1T 2T 2T 2T 3T 3T 4T 4T 4T 5T 6T 6T 6T
1T 1T 2T 2T 2T 3T 4T 4T 4T 5T 6T 6T 6T
1T 2T 2T 2T 3T 4T 4T 4T 5T 6T 6T 6T 7T
0

Case 1: 3T 9T BAI
Case 2: 3T 9T 1W
Case 3: 1T 2T 3T 4T 6T 7T
Case 4: 1T 3T 4T 6T
Case 5: 1T 2T 3T 4T 5T
Case 6: 1T 2T 3T 4T 6T 7T
Case 7: 1T 4T 5T 6T
Case 8: 2T 3T 4T 5T
Case 9: 1T 2T 3T 4T 6T
Case 10: 1T 2T 3T 4T 5T 6T 7T
Case 11: 1T 2T 3T 5T
Case 12: 1T 2T 4T 5T
Case 13: 1T 3T 4T 5T 6T 7T
Case 14: 1T 2T 3T
Case 15: 3T 4T 5T 6T 7T
Case 16: 1T 3T 4T 5T 6T
Case 17: 1T 3T 4T 6T 7T
Case 18: 2T 3T 4T
Case 19: 1T 4T
Case 20: 2T 6T
*/


最後更新:2017-04-04 07:03:48

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