12.9 訓練 E - Ternary Password
比賽的時候這題是zjy寫的,1A了
下來重寫,因為一直沒考慮到6 2 2 221110 這種情況,wa了好幾次。
/*
author:jxy
lang:C/C++
university:China,Xidian University
**If you need to reprint,please indicate the source**
*/
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <queue>
#define INF 1E9
using namespace std;
int main()
{
int n,a,b,na,nb;
string s;
while(~scanf("%d%d%d",&n,&a,&b))
{
cin>>s;
if(a+b>n){cout<<-1<<endl;continue;}
int i;
na=nb=0;
int ans=0;
bool flag=0;
for(i=0;i<s.size();i++)
{
if(s[i]=='0')na++;
if(s[i]=='1')nb++;
}
for(i=0;i<s.size();i++)
{
flag=0;
if(na>a&&s[i]=='0')
{
ans++;na--;
if(nb<b){s[i]='1';nb++;}
else s[i]='2';
}
else if(nb>b&&s[i]=='1')
{
ans++;nb--;
if(na<a){s[i]='0';na++;}
else s[i]='2';
}
}
for(i=0;i<s.size();i++)
if(s[i]=='2')
{
if(na<a){s[i]='0';na++;ans++;}
else if(nb<b){s[i]='1';nb++;ans++;}
}
cout<<ans<<endl;
cout<<s<<endl;
}
return 0;
}
最後更新:2017-04-02 22:15:57