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并发实战题（一）
实现一个流控程序。控制客户端每秒调用某个远程服务不超过N次，客户端是会多线程并发调用，需要一个轻量简洁的实现，大家看看下面的一个实现，然后可以自己写一个实现。
import java.util.Date;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Semaphore;
import java.util.concurrent.TimeUnit;
public class Test {
final static int MAX_QPS = 10;
final static Semaphore semaphore = new Semaphore(MAX_QPS);
public static void main (String ... args) throws Exception {
Executors.newScheduledThreadPool(1).scheduleAtFixedRate(new Runnable() {
@Override
public void run() {
semaphore.release(MAX_QPS/2);
}
}, 1000, 500, TimeUnit.MILLISECONDS);
//lots of concurrent calls:100 * 1000
ExecutorService pool = Executors.newFixedThreadPool(100);
for (int i=100;i>0;i--) {
final int x = i;
pool.submit(new Runnable() {
@Override
public void run() {
for (int j=1000;j>0;j--) {
semaphore.acquireUninterruptibly(1);
remoteCall(x, j);
}
}
});
}
pool.shutdown();
pool.awaitTermination(1, TimeUnit.HOURS);
System.out.println("DONE");
}
private static void remoteCall(int i, int j) {
System.out.println(String.format("%s - %s: %d %d",new Date(),
Thread.currentThread(), i, j));
}
}
文章转自 并发编程网-ifeve.com
最后更新：2017-05-22 20:04:40