617
a letter and a number
a letter and a number
时间限制：3000 ms | 内存限制：65535 KB
难度：1
- 描述
-
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).- 输入
- On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).
- 输出
- for each case, you should the result of y+f(x) on a line
- 样例输入
-
6 R 1 P 2 G 3 r 1 p 2 g 3
- 样例输出
-
19 18 10 -17 -14 -4
查看代码---运行号：252173----结果：Accepted
运行时间：2012-10-05 11:36:47 | 运行人:huangyibiao
01.#include <iostream>
02.using
namespace std;
03.
04.int
main()
05.{
06.int
testNum;
07.cin >> testNum;
08.char
letterX;
09.int
numY;
10.while
(testNum--)
11.{
12.cin >> letterX >> numY;
13.if
(letterX - 'a'
>= 0)//小写
14.{
15.cout << numY - (letterX -
'a' ) - 1 << endl;//别忘了-1
16.}
17.else
18.cout << numY + (letterX -
'A') + 1 << endl;//别忘了加1
19.}
20.return
0;
21.}
最后更新：2017-04-02 15:14:53