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张志宇 SERVELET JSP学习讲义-08_SERVLET如何从上一个页面取得参数
首先，servlet如下编写代码：
package com.zzk.cn;
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
public class ThreeParams extends HttpServlet{
private static final long serialVersionUID = 1L;
@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.setContentType("text/html;charset=GBK");
//解决post方式提交内容的乱码
//一定要写在存取第一个参数之前
request.setCharacterEncoding("GBK");
//解决get方式乱码问题：-->URIEncoding="GBK"
PrintWriter out = response.getWriter();
out.println(request.getParameter("param1"));
out.println("<br>");
out.println(request.getParameter("param2"));
out.println("<br>");
out.println(request.getParameter("param3"));
out.println("<br>");
System.out.println("in doGet");
}
@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
System.out.println("in doPost");
doGet(request, response);
}
}
页面输出：
1
2是
2
ThreeParams.htm里post方式
<form name="form1" method="post" action="ThreeParams">
<table width="343" border="1">
<tr>
<td width="92">param1</td>
<td width="94"><input name="param1" type="text" /> </td>
</tr>
<tr>
<td>param2</td>
<td><label>
<input name="param2" type="text" />
</label></td>
</tr>
<tr>
<td>param3</td>
<td><input name="param3" type="text" /></td>
</tr>
<tr>
<td> </td>
<td><label>
<input type="submit" value="提交" />
</label></td>
</tr>
</table>
</form>
传参成功
tomcat里显示：
in Dopost in Doget
然后将html改为get方式：
传参成功
tomcat里显示：
in doGet
最后更新：2017-04-02 22:16:18