大數相乘算法
#include <stdio.h> #include <string.h> #define MAX_LENGTH 1000 /************************************************************************/ /* 功能:計算兩個超大數的乘積 /* 參數:source1:被乘數,字符型數組,長度最大為MAX_LENGTH /* source2:乘數,字符型數組,長度最大為MAX_LENGTH /* result:計算結果,並返回 /************************************************************************/ void Multiply(char *source1, char *source2, char *result) { int i, j, k, m, n, temp; char tempArr[MAX_LENGTH + 1]; int length1, length2; int carryBit = 0; int start = 0; length1 = strlen(source1); length2 = strlen(source2); for (i = 0; i < MAX_LENGTH; i++) { result[i] = '0'; } for (i = length1 - 1; i >= 0; i--) { k = 0; carryBit = 0; for (j = length2 - 1; j >= 0; j--) { temp = (source2[j] - '0') * (source1[i] - '0') + carryBit; tempArr[k++] = temp % 10 + '0'; carryBit = temp / 10; } while (carryBit != 0) { tempArr[k++] = carryBit % 10 + '0'; carryBit /= 10; } for (m = start, n = 0; n < k; m++, n++) { temp = result[m] - '0' + tempArr[n] - '0' + carryBit; carryBit = temp / 10; result[m] = temp % 10 + '0'; } while (carryBit) { result[++m] = carryBit % 10 + '0'; carryBit /= 10; } start++; } result[++m] = '\0'; } int main() { char source1[MAX_LENGTH]; char source2[MAX_LENGTH]; char result[MAX_LENGTH]; int i, begin; scanf("%s%s", source1, source2); Multiply(source1, source2, result); // 找到最後一個前導0的位置 begin = strlen(result) - 1; for (i = begin; i >= 0; i--) { if (result[i] == '0') { begin--; } else { break; } } for (i = begin; i >= 0; i--) { printf("%c", result[i]); } putchar(10); return 0; }
最後更新:2017-04-03 18:52:03