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VB6下BASE64轉換

Option Explicit

Private Const BASE64CHR         As String = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/="
Private psBase64Chr(0 To 63)    As String

'從一個經過Base64的字符串中解碼到源字符串
Public Function DecodeBase64String(str2Decode As String) As String
    DecodeBase64String = StrConv(DecodeBase64Byte(str2Decode), vbUnicode)
End Function

'從一個經過Base64的字符串中解碼到源字節數組
Public Function DecodeBase64Byte(str2Decode As String) As Byte()

    Dim lPtr            As Long
    Dim iValue          As Integer
    Dim iLen            As Integer
    Dim iCtr            As Integer
    Dim Bits(1 To 4)    As Byte
    Dim strDecode       As String
    Dim str             As String
    Dim Output()        As Byte
    
    Dim iIndex          As Long

    Dim lFrom As Long
    Dim lTo As Long
    
    InitBase
    
    '//除去回車
    str = Replace(str2Decode, vbCrLf, "")

    '//每4個字符一組(4個字符表示3個字)
    For lPtr = 1 To Len(str) Step 4
        iLen = 4
        For iCtr = 0 To 3
            '//查找字符在BASE64字符串中的位置
            iValue = InStr(1, BASE64CHR, Mid$(str, lPtr + iCtr, 1), vbBinaryCompare)
            Select Case iValue  'A~Za~z0~9+/
                Case 1 To 64:
                    Bits(iCtr + 1) = iValue - 1
                Case 65         '=
                    iLen = iCtr
                    Exit For
                    '//沒有發現
                Case 0: Exit Function
            End Select
        Next

        '//轉換4個6比特數成為3個8比特數
        Bits(1) = Bits(1) * &H4 + (Bits(2) And &H30) / &H10
        Bits(2) = (Bits(2) And &HF) * &H10 + (Bits(3) And &H3C) / &H4
        Bits(3) = (Bits(3) And &H3) * &H40 + Bits(4)

        '//計算數組的起始位置
        lFrom = lTo
        lTo = lTo + (iLen - 1) - 1
                
        '//重新定義輸出數組
        ReDim Preserve Output(0 To lTo)
        
        For iIndex = lFrom To lTo
            Output(iIndex) = Bits(iIndex - lFrom + 1)
        Next

        lTo = lTo + 1
        
    Next
    DecodeBase64Byte = Output
End Function



'將一個字節數組進行Base64編碼,並返回字符串
Public Function EncodeBase64Byte(sValue() As Byte) As String
    Dim lCtr                As Long
    Dim lPtr                As Long
    Dim lLen                As Long
    Dim sEncoded            As String
    Dim Bits8(1 To 3)       As Byte
    Dim Bits6(1 To 4)       As Byte
    
    Dim i As Integer
    
    InitBase

    For lCtr = 1 To UBound(sValue) + 1 Step 3
        For i = 1 To 3
            If lCtr + i - 2 <= UBound(sValue) Then
                Bits8(i) = sValue(lCtr + i - 2)
                lLen = 3
            Else
                Bits8(i) = 0
                lLen = lLen - 1
            End If
        Next

        '//轉換字符串為數組,然後轉換為4個6位(0-63)
        Bits6(1) = (Bits8(1) And &HFC) / 4
        Bits6(2) = (Bits8(1) And &H3) * &H10 + (Bits8(2) And &HF0) / &H10
        Bits6(3) = (Bits8(2) And &HF) * 4 + (Bits8(3) And &HC0) / &H40
        Bits6(4) = Bits8(3) And &H3F

        '//添加4個新字符
        For lPtr = 1 To lLen + 1
            sEncoded = sEncoded & psBase64Chr(Bits6(lPtr))
        Next
    Next

    '//不足4位,以=填充
    Select Case lLen + 1
        Case 2: sEncoded = sEncoded & "=="
        Case 3: sEncoded = sEncoded & "="
        Case 4:
    End Select

    EncodeBase64Byte = sEncoded
End Function


'對字符串進行Base64編碼並返回字符串
Public Function EncodeBase64String(str2Encode As String) As String
    Dim sValue()            As Byte
    sValue = StrConv(str2Encode, vbFromUnicode)
    EncodeBase64String = EncodeBase64Byte(sValue)
End Function





Private Sub InitBase()
    Dim iPtr    As Integer
    '初始化 BASE64數組
    For iPtr = 0 To 63
        psBase64Chr(iPtr) = Mid$(BASE64CHR, iPtr + 1, 1)
    Next
End Sub

 

最後更新:2017-04-02 00:06:22

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