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poj 2538 WERTYU
简单暴力的一道题，以前做过，现在就不浪费时间自己打表了。。。
粘上一种稍微聪明的方法和一种最笨的方法。。。
聪明一些的方法：
#include <cstdio>
#include <cstring>
const char dic[]=" 1234567890-=QWERTYUIOP[]\\ASDFGHJKL;'ZXCVBNM,./";
char str[1000];
int main()
{
int i,j,l,l2=strlen(dic);
while (gets(str)!=NULL)
{
l=strlen(str);
for (i=0;i<l;i++)
{
for (j=1;str[i]!=dic[j] && j<l2;j++);
if (j<l2)
printf("%c",dic[j-1]);
else
printf(" ");
}
printf("\n");
}
}
最笨的方法：
#include"stdio.h"
#include"string.h"
int main()
{
char s[100];
char a[100];
s[';'] = 'L';
s['L'] = 'K';
s['K'] = 'J';
s['J'] = 'H';
s['H'] = 'G';
s['G'] = 'F';
s['F'] = 'D';
s['D'] = 'S';
s['S'] = 'A';
s[','] = 'M';
s['M'] = 'N';
s['N'] = 'B';
s['B'] = 'V';
s['V'] = 'C';
s['C'] = 'X';
s['X'] = 'Z';
s['['] = 'P';
s['P'] = 'O';
s['O'] = 'I';
s['I'] = 'U';
s['U'] = 'Y';
s['Y'] = 'T';
s['T'] = 'R';
s['R'] = 'E';
s['E'] = 'W';
s['W'] = 'Q';
s['/'] = '.';
s['\''] = ';';
s[']'] = '[';
s['\\'] = ']';
s['.'] = ',';
s['='] = '-';
s['-'] = '0';
s['0'] = '9';
s['9'] = '8';
s['8'] = '7';
s['7'] = '6';
s['6'] = '5';
s['5'] = '4';
s['4'] = '3';
s['3'] = '2';
s['2'] = '1';
s['1'] = '`';
s[' ']=' ';
while(gets(a))
{
int i;
for(i=0;i<strlen(a);i++)
printf("%c",s[a[i]]);
printf("\n");
}
return 0;
}
最后更新：2017-04-03 05:40:02