Android實現兩次按下返回鍵退出
@Override
public boolean onKeyDown(int keyCode, KeyEvent event)
{
if(keyCode == KeyEvent.KEYCODE_BACK && event.getAction() == KeyEvent.ACTION_DOWN)
{
if((System.currentTimeMillis()-exitTime) > 2000) //System.currentTimeMillis()無論何時調用,肯定大於2000
{
Toast.makeText(getApplicationContext(), "再按一次退出程序",Toast.LENGTH_SHORT).show();
exitTime = System.currentTimeMillis();
}
else
{
finish();
System.exit(0);
}
return true;
}
return super.onKeyDown(keyCode, event);
}
第二種:
https://blog.csdn.net/carterjin/article/details/7677069
最後更新:2017-04-03 12:54:48