Android實現兩次按下返回鍵退出
@Override public boolean onKeyDown(int keyCode, KeyEvent event) { if(keyCode == KeyEvent.KEYCODE_BACK && event.getAction() == KeyEvent.ACTION_DOWN) { if((System.currentTimeMillis()-exitTime) > 2000) //System.currentTimeMillis()無論何時調用,肯定大於2000 { Toast.makeText(getApplicationContext(), "再按一次退出程序",Toast.LENGTH_SHORT).show(); exitTime = System.currentTimeMillis(); } else { finish(); System.exit(0); } return true; } return super.onKeyDown(keyCode, event); }
第二種:
https://blog.csdn.net/carterjin/article/details/7677069
最後更新:2017-04-03 12:54:48